Homework Hacks 3.6

# Popcorn Hack #1
# Step 1: Add a variable that represents temperature
temperature = 60  # You can change this value to test different conditions

# Step 2: Check if it’s a hot day
if temperature >= 80:
    print("It's a hot day")
# Step 3: Check if it’s a warm day
elif 60 <= temperature < 80:
    print("It's a warm day")
# Step 4: Check if it’s a cool day
elif 40 <= temperature < 60:
    print("It's a cool day")
# Step 5: Otherwise, print it's a cold day
else:
    print("It's a cold day")

It's a warm day

3.6.2 Hacks

// Popcorn Hack #1
let score = 85;

if (score >= 60) {
    console.log("You passed!");
} else {
    console.log("You failed! Your score is below 60.");
}

  Cell In[7], line 1
    // Popcorn Hack #1
    ^
SyntaxError: invalid syntax

3.6.3 Python Hacks

# Hack 1: Odd or Even Checker

def check_odd_even(number):
    
    if number % 2 == 0:
        return "Even"
    else:
        return "Odd"


def get_valid_number():
    while True:
        user_input = input("Enter a number to check if it's odd or even: ")
        if user_input.isdigit() or (user_input.startswith('-') and user_input[1:].isdigit()):
            return int(user_input)
        else:
            print("Invalid input. Please enter a valid number.")


while True:
    number = get_valid_number()
    result = check_odd_even(number)
    print(f"The number {number} is {result}.")
    
   
    continue_check = input("Do you want to check another number? (yes/no): ").strip().lower()
    if continue_check != 'yes':
        break


print(check_odd_even(4))  
print(check_odd_even(7))  
print(check_odd_even(10)) 
print(check_odd_even(15)) 
print(check_odd_even(0))

The number 1 is Odd.
Even
Odd
Even
Odd
Even

# Hack 2: Leap Year Checker

def is_leap_year(year):
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        return "Leap Year"
    else:
        return "Not a Leap Year"

def get_valid_year():
    while True:
        user_input = input("Enter a year to check if it's a leap year: ")
        if user_input.isdigit() or (user_input.startswith('-') and user_input[1:].isdigit()):
            return int(user_input)
        else:
            print("Invalid input. Please enter a valid year.")

while True:
    year = get_valid_year()
    result = is_leap_year(year)
    print(f"The year {year} is {result}.")
    
    continue_check = input("Do you want to check another year? (yes/no): ").strip().lower()
    if continue_check != 'yes':
        break

print(is_leap_year(2000))  
print(is_leap_year(1900))  
print(is_leap_year(2024))  
print(is_leap_year(2023))  
print(is_leap_year(1600))

The year 1999 is Not a Leap Year.
Leap Year
Not a Leap Year
Leap Year
Not a Leap Year
Leap Year

#Hack 3: Temperature Range Checker
def temperature_range(temperature):
    if temperature < 60:
        return "Cold"
    elif 60 <= temperature <= 80:
        return "Warm"
    elif temperature > 85:
        return "Hot"
    else:
        return "Moderate"

def get_valid_temperature():
    while True:
        user_input = input("Enter a temperature to check its range: ")
        if user_input.replace('.', '', 1).isdigit() or (user_input.startswith('-') and user_input[1:].replace('.', '', 1).isdigit()):
            return float(user_input)
        else:
            print("Invalid input. Please enter a valid number.")

while True:
    temperature = get_valid_temperature()
    result = temperature_range(temperature)
    print(f"The temperature {temperature}°F is considered {result}.")
    
    continue_check = input("Do you want to check another temperature? (yes/no): ").strip().lower()
    if continue_check != 'yes':
        break

print(temperature_range(55))  
print(temperature_range(65))  
print(temperature_range(75))  
print(temperature_range(85))  
print(temperature_range(90))

The temperature 100.0°F is considered Hot.
The temperature 30.0°F is considered Cold.
The temperature 60.0°F is considered Warm.
Cold
Warm
Warm
Moderate
Hot

3.6.4 Javascript Hacks

// Hack #2: Checking Voting Eligibility

function checkVotingEligibility(age) {
    if (age >= 18) {
        return "You are eligible to vote!";
    } else {
        return "You are not eligible to vote yet.";
    }
}

function getValidAge() {
    while (true) {
        let userInput = prompt("Enter your age to check voting eligibility: ");
        if (!isNaN(userInput) && userInput.trim() !== "") {
            return parseInt(userInput, 10);
        } else {
            alert("Invalid input. Please enter a valid age.");
        }
    }
}

while (true) {
    let age = getValidAge();
    let result = checkVotingEligibility(age);
    console.log(result);
    
    let continueCheck = prompt("Do you want to check another age? (yes/no): ").trim().toLowerCase();
    if (continueCheck !== 'yes') {
        break;
    }
}

// Hack 2: Grade Calculator

function getGrade(score) {
    if (score >= 90) {
        return "Grade: A";
    } else if (score >= 80) {
        return "Grade: B";
    } else if (score >= 70) {
        return "Grade: C";
    } else {
        return "Grade: F";
    }
}

console.log(getGrade(95));  
console.log(getGrade(85));  
console.log(getGrade(75));  
console.log(getGrade(65));  
console.log(getGrade(50));  

  Cell In[6], line 1
    // Hack 2: Grade Calculator
    ^
SyntaxError: invalid syntax

// Hack 3: Temperature Converter
function convertTemperature(value, scale) {
    if (scale === "C") {
        return (value * 9/5) + 32 + "°F";
    } else if (scale === "F") {
        return (value - 32) * 5/9 + "°C";
    } else {
        return "Error: Invalid scale. Use 'C' for Celsius or 'F' for Fahrenheit.";
    }
}

console.log(convertTemperature(0, "C"));    
console.log(convertTemperature(32, "F"));   
console.log(convertTemperature(100, "C"));  
console.log(convertTemperature(212, "F"));  
console.log(convertTemperature(50, "X"));